this post was submitted on 09 Jan 2024
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[–] NorthWestWind@lemmy.world 0 points 8 months ago (1 children)

The circle could've been done in one equation

[–] Ashelyn@lemmy.blahaj.zone 0 points 8 months ago (1 children)

One equation, sure, but not in one valid function (without making it parametric anyways)

[–] NorthWestWind@lemmy.world 0 points 8 months ago (1 children)

x^2^+y^2^=1
or, in this case
(x-2)^2^+(y-2)^2^=1

[–] bob_lemon@feddit.de 0 points 8 months ago

A that's a single equation alright. But as the previous poster pointed out, it's not a function.