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Correct = reductive?
First, I was talking about quantum encryption, not quantum cryptography, which is a bit more broad. Second, we already have cryptographic algorithms that run on classical computers that are not crackable by quantum computers, known as lattice-based cryptography which are way more practical than anything quantum cryptography could offer.
Shor's algorithm. Yes, it breaks asymmetrical ciphers like RSA, but we have developed alternatives already it cannot break, like Kyber.
Classical key exchange algorithms prevent someone from reading your key if they intercept the data packets between you. QKD is entirely impractical because it does not achieve this. Rather than preventing someone from reading your key if they intercept the data packets, it merely allows you to detect if someone is intercepting the data packets. You see, in regular cryptography, you want people to be able to intercept your data. It's necessary for something like the internet to work, because packets of data have to be passed around the whole world, and it would suck if your packets got lost simply because someone read them in transit, which is why QKD is awful. If a single person reads the data packet in transit then they would effectively deny service to the recipient.
One-time pad encryption is awful as I already explained, it would cut the entire internet bandwidth in half because if you wanted to transmit 10 gigabytes of data you would also need to transmit 10 gigabyte key. QKD is also awful for the fact that it would be unscalable to an "internet" because of how easy it is to deny service. It also doesn't even guarantee you can detect someone snooping your packets because it is susceptible to a man-in-the-middle attack. Sure, the Diffie-Hellman Key Exchange is also susceptible to a man-in-the-middle attack, but we solve this using public key infrastructure. You cannot have public key infrastructure for quantum cryptography.
The only proposed quantum digital signature algorithms are unscalable because they rely on Holevo's theorem, which basically says there is a limited amount of information about the quantum state of a qubit you can gather from a single measurement, thus creating a sort of one-way function that can be used for digital signatures. The issue with this is that Holevo's theorem also says you can acquire more information if you have more copies of the same qubit, i.e. it means every time you distribute a copy of the public key, you increase the probability someone could guess it. Public keys would have to be consumable which would entirely prevent you from scaling it to any significantly large network.
You are living in fairy tale lala land. Come back down to reality. If you offer someone an algorithm that is impossible to break in a trillion, trillion years, and another algorithm that is in principle impossible to break, but the former algorithm is twice as efficient, then every company on the entirety of planet earth will choose the former. No enterprise on earth is going to double their expenses for something entirely imaginary that could never be observed in practice. You are really stuck in delulu town if you unironically think the reason one-time pads aren't used practically is due to lack of secure key distribution.
Even prior to the discovery of Shor's algorithm, we were issuing DHKE which, at the time, was believed to be pretty much an unbreakable way to share keys. Yet, even in this time before people knew DHKE could be potentially broken by quantum computers, nobody used DHKE to exchange keys for one-time pads. DHKE is always used to exchange keys for symmetrical ciphers like AES. AES256 is not breakable by quantum computers in practice as even a quantum computer would require trillions of years to break it. There is zero reason to use a one-time pad when something like AES exists. It's the industry standard for a reason and I bet you my entire life savings we are not going to abandon it for one-time pads ever.