this post was submitted on 10 Oct 2024
167 points (98.3% liked)
Asklemmy
43945 readers
572 users here now
A loosely moderated place to ask open-ended questions
Search asklemmy ๐
If your post meets the following criteria, it's welcome here!
- Open-ended question
- Not offensive: at this point, we do not have the bandwidth to moderate overtly political discussions. Assume best intent and be excellent to each other.
- Not regarding using or support for Lemmy: context, see the list of support communities and tools for finding communities below
- Not ad nauseam inducing: please make sure it is a question that would be new to most members
- An actual topic of discussion
Looking for support?
Looking for a community?
- Lemmyverse: community search
- sub.rehab: maps old subreddits to fediverse options, marks official as such
- !lemmy411@lemmy.ca: a community for finding communities
~Icon~ ~by~ ~@Double_A@discuss.tchncs.de~
founded 5 years ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
Oh switching to metric is a great idea.
Denmark :)
American here, got stationed in Italy for a few years. Learning Celsius was easy with this in mind:
0 freezing
10 cool
20 nice
30 hot
40 sweltering
If you need to do the actual calculation, double the celsius value, subtract the tens digit (i.e. -10%), add 32. For example:
Double it: 20 * 2 = 40
Subtract the tens digit: 40 - 4 = 36
Add 32: 36+32 = 68
Cool!!
Or a "good enough" rough estimate is: double (the Celsius number) + 30
(0 * 2) + 30 = 30F freezing
(10 * 2) + 30 = 50F cool
(20 * 2) + 30 = 70F nice
(30 * 2) + 30 = 90F hot
(40 * 2) + 30 = 110F sweltering
In reverse: subtract 30 (from the Fahrenheit number), and divide by 2
(30F - 30) / 2 = 0 C freezing
(40F - 30) / 2 = 5 C freezing
(50F - 30) / 2 = 10 C cool
(60F - 30) / 2 = 15 C cool
(70F - 30) / 2 = 20 C nice
(80F - 30) / 2 = 25 C nice
(90F - 30) / 2 = 30 C hot
(100F - 30) / 2 = 35 C hot
(110F - 30) / 2 = 40 C sweltering
(120F - 30) / 2 = 45 C start praying