this post was submitted on 10 Aug 2024
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[–] observantTrapezium@lemmy.ca 86 points 1 month ago (26 children)

Astrophysicist here. Yes, space is crazy, but interesting things to keep in mind:

  1. The size of a star is determined by something called the photosphere. With those extremely massive stars, you can be hundreds of millions of kilometres "inside" and not yet know it.
  2. Similar story with supermassive black holes, from the perspective of an astronaut falling in, they wouldn't really be able to tell when they cross the horizon because the tidal forces there are very small (they will inevitably fall towards the centre and get spaghettified at some point)
[–] SanndyTheManndy@lemmy.world 1 points 1 month ago (5 children)

What really are gravitational waves? Are they like electromagnetic waves? Do they cause orbital decay? I have so many questions.

[–] observantTrapezium@lemmy.ca 3 points 1 month ago (1 children)

They are quite similar to electromagnetic waves, but also quite different. They are produced by masses accelerating (just like EM waves are produced by charges accelerating), and indeed cause orbital decay. But this orbital decay is only important in relativistic systems (so the Earth, which is orbiting the sun at 0.0001 the speed of light, is not going to fall into the sun because of gravitational waves).

[–] psud@aussie.zone 1 points 3 weeks ago (1 children)

Surely they're more like ocean waves; EM waves are electric and magnetic fields pulling each other up by their boot straps. Gravity waves are distortions in spacetime

[–] observantTrapezium@lemmy.ca 1 points 3 weeks ago

EM and gravitational waves are seen as analogous because as I wrote, they are produced by acceleration of charges and masses, respectively. The physics behind them is very different (described by Maxwell's equations for EM and Einstein field equations for GW), but all systems that have waves in them (including sound in the air, waves on the surface of water etc.) can be approximated as linear for small perturbations, which means that they satisfy the wave equation at that regime.

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