pankuleczkapl

In criminal cases. In civil suits someone always loses, so an average person cannot win more than 50% of cases.

Finally the mathematically correct answer! Thank you for typing this out

Afaik dreams get erased because you move and your brain tries to switch to day mode (so that your dream experiences don't confuse you when you're awake). The easiest way to write down your dreams precisely is to try and wake up while still laying in bed, and write down your dreams when you're not as eepy but still in bed.

Mads Mikkelsen

Also called "real estate"

If the licence is already open source then they can't do shit. Unfortunately, they have other methods of discouraging programmers from working on the project, but ultimately open source will prevail.

I think if it was democratic, I would trust it even less. Relying on democracy in a community when specialist knowledge is required to understand a topic is a major factor that contributed to the creation of such abominations as anti-vaxxers, flat-earthers etc.

Int is definitely not injective when you consider noncontinuous functions (such as f(X)={1 iff X=0, else 0}). If you consider only continuous functions, then unfortunately 1-Int is also not injective. Consider for example e^x and 2e^x. Unfortunately your idea with equivalence classes also fails, as for L = 1 - Int, L(f) = L(g) implies only that L(f-g) = 0, so for f(X)=X and g(X)=X + e^x L(f) = L(g)

After careful consideration I have come to the conclusion that the inverse of the operator L is obviously not 1/L and you are absolutely right. This derivation is complete nonsense, my apologies. In fact no such inverse can even exist for the operator 1 - integral, as this function is not an injection.

Except the first assumption that e^x = its own integral, everything else actually makes sense (except the DX are in the wrong powers). You simply treat the "1" and "integral dx" as operators, formally functions from R^R into R^R and "(0)" as calculating the value of the operator on a constant-valued function 0. EDIT: the step 1/(1-integral) = the limit of a certain series is slightly dubious, but I believe it can be formally proven as well. EDIT 2: I was proven wrong, read the comments

Again, if you properly separate your identities, than the answer to both questions is simply impossible, since you are not the one figuring on the bill. The only thing they can achieve is link you to some IP behind 2 VPNs and 5 proxies, good luck to them if they want to dig through all that while avoiding you noticing and simply deleting all data from one of them making you completely separated from any illegal activity.

I can host an instance. I don't care about "raiding". If you get raided, it means you have not properly separated your online and real identities.