this post was submitted on 16 May 2024
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  • Show that the infinite multiplication (1+1/1)(1+1/2)(1+1/3)... does not converge.
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[–] zkfcfbzr@lemmy.world 0 points 5 months ago* (last edited 5 months ago) (1 children)

solutionThe terms can be rewritten as:

(2/1) * (3/2) * (4/3) * ... * ((n+1)/n) * ...

Each numerator will cancel with the next denominator. In total everything cancels, so the answer is the empty product, 1.

...Wait...

Uhm, ignore that. Rather, consider the products we get when multiplying. We get: 2/1. 6/2. 24/6. Etc. That is, we have:

Π (n = 1 to k) (n+1)/n = (k+1)! / k! = (k+1)k!/k! = k+1

k+1 clearly goes to infinity as k → ∞, so our product diverges to infinity.

[–] Successful_Try543@feddit.de 0 points 5 months ago* (last edited 5 months ago)

::: spoiler solution Isn't this already the result of your 1st formula? As the denominator of the last fraction you wrote down, (n+1)/n, cancels out with the counter of the one right before, n/(n-1), which you didn't write down. Thus the whole product up to the nth term reads after cancellation of neighbouring counters and denominator pairs (n+1)/1 →∞ when n→∞.