this post was submitted on 09 Dec 2024
24 points (96.2% liked)

Advent Of Code

987 readers
14 users here now

An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2024

Solution Threads

M T W T F S S
1
2 3 4 5 6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25

Rules/Guidelines

Relevant Communities

Relevant Links

Credits

Icon base by Lorc under CC BY 3.0 with modifications to add a gradient

console.log('Hello World')

founded 1 year ago
MODERATORS
 

Day 9: Disk Fragmenter

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL

FAQ

you are viewing a single comment's thread
view the rest of the comments
[–] mykl@lemmy.world 2 points 2 weeks ago* (last edited 2 weeks ago)

Dart

I just mapped the filesystem onto a list holding value at each block (with -1 for spaces), and manipulated that.

It's slow, but it's honest work.

Slow version

import 'dart:math';
import 'package:collection/collection.dart';
import 'package:more/more.dart';

List<int> parse(List<String> lines) => lines.first
    .split('')
    .map(int.parse)
    .mapIndexed((i, e) => List.filled(e, (i.isOdd ? -1 : i ~/ 2)))
    .reduce((s, t) => s + t);

part1(List<String> lines) {
  var fs = parse(lines);
  var i = 0;
  while ((i = fs.indexOf(-1)) >= 0) {
    while (fs.last == -1) {
      fs.removeLast();
    }
    fs[i] = fs.removeLast();
  }
  return fs.mapIndexed((i, e) => i * e).sum;
}

Function eq = const ListEquality().equals;
part2(List<String> lines) {
  var fs = parse(lines);
  for (var target in 1.to(fs.max + 1).reversed) {
    var index = fs.indexOf(target);
    var length = fs.sublist(index).takeWhile((e) => e == target).length;
    var sseq = List.filled(length, -1);
    var space = fs
        .indices()
        .where((e) => e < index)
        .firstWhereOrNull((i) => eq(fs.sublist(i, i + length), sseq));
    if (space == null) continue;
    // Copy the file, clear old location.
    fs.replaceRange(space, space + length, List.filled(length, target));
    fs.replaceRange(index, index + length, List.filled(length, -1));
  }
  return fs.mapIndexed((i, e) => i * max(e, 0)).sum;
}

Updated version

Massive speedup from implementing a modified Knuth–Morris–Pratt algorithm -> around 0.5sec runtime for part 2.

I really don't understand why efficiently matching a sublist isn't a builtin function. Implementing it manually was half an hour of unneeded head-scratching.

import 'dart:math';
import 'package:collection/collection.dart';
import 'package:more/more.dart';

List<int> parse(List<String> lines) => lines.first
    .split('')
    .map(int.parse)
    .mapIndexed((i, e) => List.filled(e, (i.isOdd ? -1 : i ~/ 2)))
    .flattened
    .toList();

part1(List<String> lines) {
  var fs = parse(lines);
  var i = 0;
  while ((i = fs.indexOf(-1)) >= 0) {
    while (fs.last == -1) {
      fs.removeLast();
    }
    fs[i] = fs.removeLast();
  }
  return fs.mapIndexed((i, e) => i * e).sum;
}

part2(List<String> lines) {
  var fs = parse(lines);
  for (var target in 1.to(fs.max + 1).reversed) {
    var index = fs.indexOf(target);
    var length = fs.skip(index).takeWhile((e) => e == target).length;
    int? space = findSpace(index, length, fs);
    if (space == null) continue;
    // Copy the file, clear old location.
    fs.setRange(space, space + length, List.filled(length, target));
    fs.setRange(index, index + length, List.filled(length, -1));
  }
  return fs.mapIndexed((i, e) => i * max(e, 0)).sum;
}

/// Knuth–Morris–Pratt algorithm
int? findSpace(int limit, int length, List<int> fs) {
  for (var si = 0; si < limit - length + 1; si++) {
    if (fs[si] != -1) continue;
    var match = true;
    for (var ssi in 0.to(length)) {
      if (fs[si + ssi] != -1) {
        si += ssi;
        match = false;
        break;
      }
    }
    if (match) return si;
  }
  return null;
}