Programmer Humor

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submitted 2 weeks ago by 0x4E4F@infosec.pub to c/programmer_humor@programming.dev

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[–] xmunk@sh.itjust.works 95 points 2 weeks ago (3 children)

Guaranteed to sort the list in nearly instantaneous time and with absolutely no downsides that are capable of objecting.

[–] frezik@midwest.social 47 points 2 weeks ago (2 children)

You still have to check that it's sorted, which is O(n).

We'll also assume that destroying the universe takes constant time.

[–] BatmanAoD@programming.dev 42 points 2 weeks ago (2 children)

In the universe where the list is sorted, it doesn't actually matter how long the destruction takes!

[–] groet 13 points 2 weeks ago (1 children)

It actually takes a few trillion years but its fine because we just stop considering the "failed" universes because they will be gone soon™ anyway.

[–] MBM@lemmings.world 8 points 2 weeks ago

Eh, trillion is a constant

[–] FiskFisk33@startrek.website 8 points 2 weeks ago

amortized O(0)

[–] Benjaben@lemmy.world 9 points 2 weeks ago (1 children)

We'll also assume that destroying the universe takes constant time.

Well yeah just delete the pointer to it!

[–] PoolloverNathan@programming.dev 2 points 2 weeks ago

universe.take()

[–] vithigar@lemmy.ca 16 points 2 weeks ago (1 children)

Except you missed a bug in the "check if it's sorted" code and it ends up destroying every universe.

[–] db2@lemmy.world 7 points 2 weeks ago

There's a bug in it now, that's why we're still here.