this post was submitted on 28 May 2024
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[–] Thunderwolf@lemmy.world -1 points 5 months ago* (last edited 5 months ago) (1 children)

I haven't seen anyone mention this yet, so here's how I understand it. The feather falls slower in non-vacuum conditions because it reaches its terminal velocity much more quickly than the bowling ball.

Edit: terminal velocity: https://en.m.wikipedia.org/wiki/Terminal_velocity

Also edit: https://ucscphysicsdemo.sites.ucsc.edu/physics-5a6a/coin-and-feather/#:~:text=Because%20the%20feather%20has%20a,small%2C%20the%20feather%20falls%20slowly.

[–] Shareni@programming.dev 1 points 5 months ago (1 children)

How would it reach terminal velocity in a vacuum?

[–] Thunderwolf@lemmy.world 0 points 5 months ago (1 children)

I imagine terminal velocity with no air resistance would be 9.8m/s/s. I was saying that the feather reaches terminal velocity more quickly than a bowling ball in non-vacuum conditions

[–] 0ops@lemm.ee 1 points 5 months ago

9.8 m/s/s is acceleration due to gravity, not a velocity, or its units would be m/s